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<?php
$a = array('<foo>','bar','baz','&blong&', 'xc3xa9');
echo 'Normal : ', json_encode($a), 'n';
echo 'Tags : ', json_encode($a, JSON_HEX_TAG), 'n';
echo 'Apos : ', json_encode($a, JSON_HEX_APOS), 'n';
echo 'Quot : ', json_encode($a, JSON_HEX_QUOT), 'n';
echo 'Amp : ', json_encode($a, JSON_HEX_AMP), 'n';
echo 'Unicode : ', json_encode($a, JSON_UNESCAPED_UNICODE), 'n';
echo 'Toutes : ', json_encode($a, JSON_HEX_TAG | JSON_HEX_APOS | JSON_HEX_QUOT | JSON_HEX_AMP | JSON_UNESCAPED_UNICODE), 'nn';
$b = array();
echo 'Tableau vide sous forme de tableau : ', json_encode($b), 'n';
echo 'Tableau vide sous forme d'objet : ', json_encode($b, JSON_FORCE_OBJECT), 'nn';
$c = array(array(1,2,3));
echo 'Tableau non-associatif sous forme de tableau : ', json_encode($c), 'n';
echo 'Tableau non-associatif sous forme d'objet : ', json_encode($c, JSON_FORCE_OBJECT), 'nn';
$d = array('foo' => 'bar', 'baz' => 'long');
echo 'Tableau associatif affiché comme objet: ', json_encode($d), 'n';
echo 'Tableau associatif affiché comme objet: ', json_encode($d, JSON_FORCE_OBJECT), 'nn';
?>
I tried to parse a JSON file using PHP. But I am stuck now.
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This is the content of my JSON file:
And this is what I have tried so far:
But because I don't know the names (like 'John'
, 'Jennifer'
) and all available keys and values (like 'age'
, 'count'
) beforehand, I think I need to create some foreach loop.
I would appreciate an example for this.
localheinzTo iterate over a multidimensional array, you can use RecursiveArrayIterator
Output:
I can't believe so many people are posting answers without reading the JSON properly.
If you foreach iterate $json_a
alone, you have an object of objects. Even if you pass in true
as the second parameter, you have a two-dimensional array. If you're looping through the first dimension you can't just echo the second dimension like that. So this is wrong:
To echo the statuses of each person, try this:
FlimmThe most elegant solution:
Remember that the json-file has to be encoded in UTF-8 without BOM. If the file has BOM, then json_decode will return NULL.
Alternatively:
It's completely beyond me that no one pointed out that your begining 'tags' are wrong. You're creating an object with {}, while you could create an array with [].
With this change, the json will be parsed as an array instead of an object. And with that array, you can do whatever you want, like loops etc.
Loop through the JSON with a foreach
loop as key-value pairs. Do type-checking to determine if more looping needs to be done.
When you decode a json string, you will get an object. not an array. So the best way to see the structure you are getting, is to make a var_dump of the decode. (this var_dump can help you understand the structure, mainly in complex cases).
The quickest way to echo all json values is using loop in loop, the first loop is going to get all the objects and the second one the values...
You have to give like this:
Which gives the result :
ElmoI am using below code for converting json to array in PHP
,If JSON is valid then json_decode()
works well, and will return an array,But in case of malformed JSON It will return NULL
,
If in case of malformed JSON, you are expecting only array, then you can use this function,
If in case of malformed JSON, you want to stop code execution, then you can use this function,
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